Question:hard

If \[ u=\sqrt{a^2\cos^2\theta+b^2\sin^2\theta} + \sqrt{a^2\sin^2\theta+b^2\cos^2\theta}, \] then the difference between the maximum and minimum values of \(u^2\) is

Show Hint

For expressions involving \(\sqrt A+\sqrt B\), square first. Then use identities such as \(\sin^2\theta\cos^2\theta=\frac14\sin^22\theta\) to determine extrema.
Updated On: Jul 29, 2026
  • \((a+b)^2\)
  • \((a-b)^2\)
  • \(2\sqrt{a^2+b^2}\)
  • \(2\sqrt{a^2-b^2}\)
Show Solution

The Correct Option is B

Solution and Explanation

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