Question:medium

If \(u=e^{xy}\), then the value of \(\displaystyle \frac{\partial^2u}{\partial x^2}+\frac{\partial^2u}{\partial y^2}\) at \((1,1)\) is

Show Hint

For \(u=e^{xy}\), remember that \(\frac{\partial}{\partial x}(e^{xy})=y e^{xy}\) and \(\frac{\partial}{\partial y}(e^{xy})=x e^{xy}\).
  • \(e\)
  • \(2e\)
  • \(1\)
  • \(0\)
Show Solution

The Correct Option is B

Solution and Explanation

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