If three tube lights with power 10 W, 25 W and 50 W are connected in parallel to a source voltage V, then the effective power of the combination is
Show Hint
In series, the effective power is calculated like parallel resistors: \( \frac{1}{P_{\text{eff}}} = \frac{1}{P_1} + \frac{1}{P_2} + \frac{1}{P_3} \).
In parallel, it is simple addition.