Question:medium
If \( \theta = \cot^{-1}\sqrt{\frac{1-x}{1+x}} \), then \( \sec^2 \theta \) is equal to
If \( \theta = \cot^{-1}\sqrt{\frac{1-x}{1+x}} \), then \( \sec^2 \theta \) is equal to
Show Hint
Convert inverse trig expressions into basic trig ratios before applying identities.
Updated On: Apr 21, 2026
- \( \frac{1+x}{2} \)
- \( \frac{1-x}{2} \)
- \( \frac{2}{1-x} \)
- \( x \)
- \( 2x \)
Show Solution
The Correct Option is C
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