Question:medium

If the sum of two numbers is 10 and the difference of their squares is 20, then these numbers are:

Show Hint

If both \(x+y\) and \(x^2-y^2\) are given, first use \[ x^2-y^2=(x-y)(x+y) \] to find \(x-y\), then solve the two linear equations.
  • 8 and 2
  • 6 and 4
  • 7 and 3
  • 5 and 5
Show Solution

The Correct Option is B

Solution and Explanation


Step 1: Form the equations.
Let the numbers be \(x\) and \(y\). Given: \[ x+y=10 \] and \[ x^2-y^2=20 \] Using the identity: \[ (x-y)(x+y)=20 \] Substituting \(x+y=10\), \[ 10(x-y)=20 \] \[ x-y=2 \]

Step 2: Solve simultaneously.
\[ x+y=10 \] \[ x-y=2 \] Adding, \[ 2x=12 \] \[ x=6 \] Substituting into \(x+y=10\), \[ y=4 \] Thus, the two numbers are \[ {6 \text{ and } 4} \] Hence, the correct answer is Option (B).
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