If the square of the matrix $\begin{pmatrix} a & b \\ a & -a \end{pmatrix}$ is the unit matrix, then $b$ is equal to:
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The square of a matrix \( \begin{pmatrix} a & b c & -a \end{pmatrix} \) is always a scalar matrix of the form \( (a^2+bc)I \). Setting this equal to \( I \) gives \( a^2+bc=1 \). In our case, \( c=a \), so \( a^2+ab=1 \).