Question:medium

If the roots of the quadratic equation $x^2 - 2px + q^2 = 0$ are real and distinct, then:

Show Hint

"Real and distinct" strictly translates to a strict inequality ($>$). This immediately rules out options (C) and (D) containing $\ge$ and $\le$.
Updated On: May 31, 2026
  • $|p| > |q|$
  • $|p| < |q|$
  • $p^2 \ge q^2$
  • $p^2 \le q^2$
Show Solution

The Correct Option is A

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