Question:medium

If the radius of the first Bohr orbit is $r$, then the de Broglie wavelength of the electron in the $4^{\text{th}}$ orbit is

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Physics Tip : In SHM, $v=\dfrac{dx}{dt}$ and maximum velocity is $a\omega$.
Updated On: Apr 23, 2026
  • $\omega\cos\phi$
  • $a\omega$
  • $\omega\cos2\phi$
  • $-a\omega\cos2\phi$
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The Correct Option is B

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