Question:medium

If the radiation emitted by a perfect radiator has maximum intensity at a wavelength of 2900 Å, the intensity of radiation emitted by it is (Stefan-Boltzmann's constant = \(5.67 \times 10^{-8}\) Wm\(^{-2}\)K\(^{-4}\) and Wein's constant = \(2.9 \times 10^{-3}\) mK)

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This is a two-step problem common in thermal radiation. 1. Use Wien's Law (\(\lambda_{max} T = b\)) to find the temperature from the peak wavelength. 2. Use the Stefan-Boltzmann Law (\(I = \sigma T^4\)) to find the total intensity from the temperature. Make sure all units are in the SI system before calculating.

Updated On: Mar 30, 2026

\(5.67 \times 10^8\) Wm\(^{-2}\)
\(5.67\) Wm\(^{-2}\)
5670 Wm\(^{-2}\)
2.9 Wm\(^{-2}\)

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The Correct Option is A

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