The emf equation of an alternator is \( E = 4.44 k_w \Phi f T \), and this value depends only on frequency, flux per pole, winding factor and turns per phase, not directly on the number of poles.
So changing the pole count alone, with frequency held constant, leaves the generated emf unaffected.
Think of the emf equation from first principles: each pole produces one half-cycle of induced voltage in a conductor as it sweeps past, and the frequency of the resulting waveform is fixed by how many complete electrical cycles occur per second, which is fixed here because the alternator is tied to a fixed-frequency system. Since the physical flux per pole and the number of turns in the winding are unchanged by simply adding poles, the peak flux linkage per cycle stays the same too.
Changing the number of poles simply redistributes how the fixed flux and frequency are produced mechanically; it does not change the induced voltage itself.
Therefore, the correct answer is remain the same.