Question

If the minimum force required to move a body up an inclined plane of inclination 45\(^\circ\) is 3 times the force required to just prevent it sliding down, the coefficient of friction is

Hint:

For an incline with angle \(\theta\), if the ratio of force up to force down is \(k\), then \(\mu = \tan\theta \cdot \frac{k-1}{k+1}\). Here, \(\mu = \tan(45^\circ) \cdot \frac{3-1}{3+1} = 1 \cdot \frac{2}{4} = 0.5\).

Answer 1