If the mean of the numbers $a, b, 8, 5, 10$ is $6$ and their variance is $6.8$, then $ab$ is equal to:
Show Hint
When given both mean and variance for two unknown variables, always solve for $(a+b)$ and $(a^2+b^2)$ separately. The identity $(a+b)^2 = a^2 + b^2 + 2ab$ will then directly yield the product $ab$.