If the mean and variance of a binomial variate \(X\) are \(2\) and \(1\) respectively, then the probability that \(X\) takes a value greater than one is
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For a binomial distribution,
\[
\boxed{
\text{Mean}=np,\qquad
\text{Variance}=np(1-p).
}
\]
If \(np\) and the variance are known, first determine \(p\), then \(n\).