Step 1: Get n and p
$q=0.75$, $p=0.25$, $n=4$.
Step 2: Ratio test
$\dfrac{P(1)}{P(2)}=\dfrac{4pq^3}{6p^2q^2}=\dfrac{2q}{3p}=\dfrac{2(0.75)}{3(0.25)}=2$. So $P(1)=2P(2)$, option (B).
Final Answer:
Option (B) holds for $n=4$, $p=\frac14$.
\[ \boxed{P(X=1)=2P(X=2)} \]