If the maximum value of the function $f(x) = \alpha - 4x - x^2$ is 1, then the value of $\alpha$ is equal to
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Alternatively, use differentiation: $f'(x) = -4 - 2x$. Setting $f'(x) = 0$ gives $x = -2$. Substitute this back into $f(x)$ and set equal to 1 to solve for $\alpha$.