Question:medium
If the line $\dfrac{x+1}{4} = \dfrac{y+2}{-3} = \dfrac{z-\alpha}{-2}$ passes through the point $(-1,\,-2,\,-3)$, then the value of $\alpha$ is
If the line $\dfrac{x+1}{4} = \dfrac{y+2}{-3} = \dfrac{z-\alpha}{-2}$ passes through the point $(-1,\,-2,\,-3)$, then the value of $\alpha$ is
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When a specific point is stated to lie on the line, substitute it directly into the symmetric form. All ratios must equal the same value (here 0, since the point IS on the line with parameter $\lambda = 0$ — the point of reference).
Updated On: Apr 25, 2026
- 4
- $-4$
- 3
- $-3$
- $-2$
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The Correct Option is D
Solution and Explanation
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