Question

If the ionic product of $M(OH)_2$ is $5 \times 10^{-10}$, then the molar solubility of $M(OH)_2$ in $0.1$ M NaOH is}

• A. $5 \times 10^{-12}$ M
• B. $5 \times 10^{-8}$ M
• C. $5 \times 10^{-10}$ M
• D. $5 \times 10^{-9}$ M
• E. $5 \times 10^{-16}$ M

Hint:

In common ion problems, always check whether added ion dominates equilibrium — it drastically reduces solubility.

Answer 1

The Correct Option is B