Question

If the interval of differencing being unity and \(\Delta\) be the forward difference operator, then the value of \(\Delta\left(\frac{x^2}{x^2}\right)\) is given by

• A. \(2(x+1)!\)
• B. \(2(x-1)!\)
• C. \(3(x-1)!(x-2)!\)
• D. \(3(x+1)!(x+1)!\)

Hint:

The forward difference operator: \(\Delta f(x) = f(x+1) - f(x)\).
Simplify the expression first before applying the operator.

Answer 1

The Correct Option is B