Question:hard

If the inclination of the remanent magnetic field of a 140 million years old crustal block, now located at the equator, is 50\(^\circ\), then its drift-rate is ______________ cm/yr (rounded off to two decimal places). [Use \(1^\circ=111\) km]

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Use the axial-dipole relation tan I = 2 tan(paleolatitude) to find how far (in degrees of latitude) the block has drifted from its magnetisation latitude to its present equatorial position, then convert to cm/yr.
Updated On: Jul 21, 2026
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Correct Answer: 2.3

Solution and Explanation

Alternative (table-interpolation) route — avoid a calculator's inverse-tangent key and instead use a standard tangent table:

\(\tan30^\circ=0.5774\), \(\tan31^\circ=0.6009\). Our target value \(\tan\lambda=0.5959\) lies between these two, closer to 31\(^\circ\):

\[ \text{fraction}=\dfrac{0.5959-0.5774}{0.6009-0.5774}=\dfrac{0.0185}{0.0235}\approx0.79 \]

\[ \lambda\approx30^\circ+0.79^\circ=30.79^\circ \]

This confirms \(\lambda\approx30.8^\circ\) obtained above by direct inversion.

Distance \(=30.79\times111=3417.7\) km \(=3.4177\times10^{8}\) cm.
Rate \(=\dfrac{3.4177\times10^{8}}{1.4\times10^{8}}\approx2.44\) cm/yr — the identical result via a purely tabular interpolation, safely inside the 2.3–2.5 cm/yr key range.

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