Step 1: Understand the given data.
Granule density, \(\rho_{granule} = 2.350\) g/cc.
True density, \(\rho_{true} = 3.560\) g/cc.
We need the interparticle porosity, the fraction of void space between particles within the granule bed.
Step 2: Set up the porosity relation.
Porosity compares the volume of voids to the total volume occupied by the granules:
\[ \varepsilon = 1 - \frac{\rho_{granule}}{\rho_{true}} \]
This works because \(\rho_{granule}/\rho_{true}\) is the fraction of the granule volume that is actually solid material, so one minus that fraction is the void fraction.
Step 3: Substitute and calculate.
\[ \varepsilon = 1 - \frac{2.350}{3.560} \]
\[ \frac{2.350}{3.560} = 0.660 \]
\[ \varepsilon = 1 - 0.660 = 0.340 \]
Step 4: Final Answer.
\[ \boxed{\varepsilon \approx 0.34} \]