Question:medium
If the function $f(x)=\begin{cases}\dfrac{2x^2+3x-5}{x-1}, & x \ne 1 \\ k, & x=1\end{cases}$ is continuous at $x=1$, then the value of $k$ is:
If the function $f(x)=\begin{cases}\dfrac{2x^2+3x-5}{x-1}, & x \ne 1 \\ k, & x=1\end{cases}$ is continuous at $x=1$, then the value of $k$ is:
Show Hint
Cancel common factors before applying limits in continuity problems.
Updated On: Apr 24, 2026
- $6$
- $8$
- $-6$
- $7$
- $-7$
Show Solution
The Correct Option is D
Solution and Explanation
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