Question:medium
If the focus and vertex of a parabola are at a distance of 3 units and 6 units, respectively, from the origin on the positive x-axis, then the equation of the parabola is
If the focus and vertex of a parabola are at a distance of 3 units and 6 units, respectively, from the origin on the positive x-axis, then the equation of the parabola is
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Logic Tip: Always sketch a quick diagram for conic sections. Placing $V$ at $(6,0)$ and $S$ at $(3,0)$ visually proves the parabola opens leftwards, immediately indicating a negative coefficient for the linear $x$ term.
Updated On: Apr 27, 2026
- $y^{2}=-12(x-6)$
- $y^{2}=-9(x-6)$
- $y^{2}=-16(x-6)$
- $y=16(x-6)^{2}$
- $y^{2}=14(x-6)$
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The Correct Option is A
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