Question:medium

If the first quartile is 142 and the semi-interquartile range is 18, then the third quartile is:

Show Hint

Use \[ Q_3 = Q_1+2(\text{Quartile Deviation}). \] Thus, \[ Q_3 = 142+2(18) = 178. \]
  • \(160\)
  • \(124\)
  • \(178\)
  • \(151\)
Show Solution

The Correct Option is C

Solution and Explanation


Step 1: Use the given information.
Given, \[ Q_1=142 \] and \[ \frac{Q_3-Q_1}{2}=18. \] Therefore, \[ \frac{Q_3-142}{2}=18. \]

Step 2: Solve for \(Q_3\).
Multiplying by \(2\), \[ Q_3-142=36. \] Adding \(142\) to both sides, \[ Q_3=178. \] Conclusion: \[ {178} \] Hence, the correct answer is Option (C).
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