Question:hard

If the equation \(sin3θ-cos^2θ = \frac{1}{4}\) and \(θ\in [0,π]\), then the number of solutions is...

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Study \(f(\theta)=\sin3\theta-\cos^2\theta-\frac14\) on \([0,\pi]\) and count where it crosses zero.
Updated On: Oct 1, 2026
  • \(0\)
  • \(2\)
  • \(4\)
  • \(6\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Rewrite using sin 3x
Write $\cos^2\theta=1-\sin^2\theta$. The equation becomes $\sin3\theta-\tfrac34+\sin^2\theta=0$.

Step 2: Count the crossings
Plot $g(\theta)=\sin3\theta+\sin^2\theta-\tfrac34$. It is negative at $0$, touches near zero around $\pi/6$ and crosses twice in $(0,\pi/3)$. It is negative on $(\pi/3,2\pi/3)$ and crosses twice again in $(2\pi/3,\pi)$.
A numerical scan confirms exactly 4 sign changes, option (C).

Final Answer:
Four solutions exist in $[0,\pi]$, option (C). \[ \boxed{4} \]
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