Question:medium

If the eccentricity of a hyperbola is $\sqrt{3}$, then the eccentricity of its conjugate hyperbola is:

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The elegant relationship $\frac{1}{e_1^2} + \frac{1}{e_2^2} = 1$ is incredibly powerful and appears frequently in entrance exams. Memorize it!

Updated On: May 31, 2026

$\sqrt{\frac{3}{2}}$
$\sqrt{3}$
$\frac{\sqrt{3}}{2}$
$\sqrt{2}$

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The Correct Option is A

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