Question:medium
If the de Broglie wavelengths of proton p and alpha particle \(\alpha\) are same, then
If the de Broglie wavelengths of proton p and alpha particle \(\alpha\) are same, then
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Wavelength is purely a function of momentum in de Broglie's theory.
If \(\lambda_1 = \lambda_2\), then \(p_1 = p_2\).
If you need to compare kinetic energy (\(K\)), use \(K = p^2 / 2m\). Since masses differ, their energies would be different even with the same momentum.
If \(\lambda_1 = \lambda_2\), then \(p_1 = p_2\).
If you need to compare kinetic energy (\(K\)), use \(K = p^2 / 2m\). Since masses differ, their energies would be different even with the same momentum.
Updated On: Apr 29, 2026
- both have same momentum
- both have same energy
- momentum of p is twice that of \(\alpha\)
- momentum of \(\alpha\) is twice that of p
- energy of p is twice that of \(\alpha\)
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The Correct Option is A
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