Question:medium

If the current passing through an inductor is increased by 20%, then the percentage increase in the energy stored in the inductor is

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For small percentage changes ($<5%$), you can use calculus: $\frac{\Delta U}{U} \approx 2 \frac{\Delta I}{I}$. Here, the change is 20%, which is large, so use the exact method.
Updated On: Mar 31, 2026
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The Correct Option is A

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