If the $6^{\text{th}}$ term of a G.P. is $2$, then the product of the first $11$ terms of the G.P. is equal to:
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For any G.P. with \( n \) terms, the product of all terms is \( (\text{middle term})^n \), provided \( n \) is odd. Since 11 is odd, the middle term is the \( \frac{11+1}{2} = 6^{th} \) term. Hence, \( \text{Product} = (a_6)^{11} \).