Question:medium

If the $3^{\text{rd}}$, $7^{\text{th}}$, $11^{\text{th}}$ terms of a geometric progression are $a$, $b$, $c$ respectively, then $(ac)^{4} =$

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Logic Tip: In a G.P., if the indices of three terms form an Arithmetic Progression (like 3, 7, 11 where the difference is 4), the terms themselves form a G.P., meaning the middle term squared equals the product of the extremes: $b^2 = ac$.
Updated On: Apr 27, 2026
  • $b^{8}$
  • $b^{6}$
  • $b^{4}$
  • $b^{2}$
  • $b^{12}$
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The Correct Option is A

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