Question:medium
If $\tan \alpha = \dfrac{5}{6}$ and $\tan \beta = \dfrac{1}{11}$, where $0<\alpha,\beta<\dfrac{\pi}{2}$ then $\alpha + \beta =$:
If $\tan \alpha = \dfrac{5}{6}$ and $\tan \beta = \dfrac{1}{11}$, where $0<\alpha,\beta<\dfrac{\pi}{2}$ then $\alpha + \beta =$:
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If $\tan(\theta)=1$, then $\theta = \frac{\pi}{4}$ in first quadrant.
Updated On: Apr 24, 2026
- $\frac{\pi}{6}$
- $\frac{\pi}{2}$
- $\frac{\pi}{3}$
- $\frac{\pi}{4}$
- $\frac{2\pi}{3}$
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The Correct Option is D
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