Question:medium
If \(\sum_{k = 0}^{n + 1} \binom{n+1}{k} = 512\) , then \(\sum_{k = 0}^{n} \binom{n}{k} =\)
If \(\sum_{k = 0}^{n + 1} \binom{n+1}{k} = 512\) , then \(\sum_{k = 0}^{n} \binom{n}{k} =\)
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\(\sum_{k=0}^m \binom{m}{k} = 2^m\).
Updated On: Apr 25, 2026
- 512
- 256
- 511
- 510
- 128
Show Solution
The Correct Option is B
Solution and Explanation
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