If \(\sqrt{2n} = 16\), then the value of \(n\) is

Question

If \(9^{\frac{1}{2}} - 2^{2x - 2} = 4^{x} - 3^{2x - 3}\), then \(x\) is:

Answer 1

From the equation, squaring both sides gives: \[ 2n = 16^2 = 256 \quad \Rightarrow \quad n = \frac{256}{2} = 128 \] Therefore, the answer is \(n = 128\).

List I		List II
A.	\(\sqrt{\frac{0.81\times0.484}{0.064\times6.25}}\)	I.	0.024
B.	\(\sqrt{\frac{0.204\times42}{0.07\times3.4}}\)	II.	0.99
C.	\(\sqrt{\frac{0.081\times0.324\times4.624}{1.5625\times0.0289\times72.9\times64}}\)	III.	50
D.	\(\sqrt{\frac{9.5\times0.085}{0.0017\times0.19}}\)	IV.	6

If \(\sqrt{2n} = 16\), then the value of \(n\) is

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The Correct Option is C

Solution and Explanation

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