Question:medium

If resistance of a conductor at $20^\circ$C is $10\Omega$, then the resistance at $80^\circ$C is $[\alpha = 4 \times 10^{-3} \ ^\circ\text{c}^{-1}]$

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Always calculate the temperature difference $\Delta T$ first. Be careful with decimal places when multiplying by $\alpha$ as it's usually a small number (e.g., $10^{-3}$ or $10^{-4}$).
Updated On: Apr 21, 2026
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