If $p$ is the length of perpendicular from the origin to the line whose intercepts on the axes are $a$ and $b$ respectively, then $\frac{1}{a^2} + \frac{1}{b^2}$ equals
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Geometry Tip: This is a standard geometric property connecting intercepts to origin distance. Memorizing $\frac{1}{p^2} = \frac{1}{a^2} + \frac{1}{b^2}$ can instantly solve similar optimization or locus problems.