Question:medium
If \(P=Fv\sin\beta t\), where \(F\) is force and \(v\) is velocity, then the dimensions of \(P\) and \(\beta\) are
If \(P=Fv\sin\beta t\), where \(F\) is force and \(v\) is velocity, then the dimensions of \(P\) and \(\beta\) are
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The angle of \(\sin\), \(\cos\), or \(\tan\) must always be dimensionless. Use this to find unknown dimensions.
Updated On: May 7, 2026
- \(ML^2T^{-3},\ T^{-1}\)
- \(MLT^{-2},\ T^{-2}\)
- \(ML^2T^{-1},\ T^{-1}\)
- \(ML^2T^3,\ T^{-2}\)
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The Correct Option is A
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