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If $P = \begin{pmatrix} 1 & \alpha & 3 \\ 1 & 3 & 3 \\ 2 & 4 & 4 \end{pmatrix}$ is the adjoint of a $3 \times 3$ matrix A and $det(A) = 4$, then $\alpha =$

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$|adj(A)| = |A|^{n-1}$. This is a very common property for competitive exams.

Updated On: May 18, 2026

22
11
3
4

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The Correct Option is B

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