Question:medium

If \(P(\alpha,\alpha+1)\) is the foot of the perpendicular drawn from the origin to the line \(L\) and the \(x\)-intercept of \(L\) is \[ \left(-\frac52,0\right), \] then the sum of the squares of the distances from the origin to all such possible points \(P\) is

Show Hint

If \((x_1,y_1)\) is the foot of the perpendicular from the origin to a line, then the line can be written directly as \[ x_1x+y_1y=x_1^2+y_1^2. \] This avoids finding slopes and makes intercept conditions easy to apply.
Updated On: Jul 29, 2026
  • \(\dfrac{45}{8}\)
  • \(\dfrac{15}{2}\)
  • \(\dfrac{12}{5}\)
  • \(\dfrac{10}{7}\)
Show Solution

The Correct Option is A

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