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If $P(A/B)=\frac{1}{2}, P(B/A)=\frac{1}{3}$ and $P(A\cap B)=\frac{1}{6}$ then $P(A\cup B)$ is
If $P(A/B)=\frac{1}{2}, P(B/A)=\frac{1}{3}$ and $P(A\cap B)=\frac{1}{6}$ then $P(A\cup B)$ is
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Logic Tip: Ensure you maintain consistent notation. Many exams use $P(A/B)$ to represent conditional probability $P(A|B)$. Remember that the event given *after* the slash or pipe is the one that goes in the denominator.
Updated On: Apr 27, 2026
- $\frac{1}{3}$
- $\frac{1}{2}$
- $\frac{2}{9}$
- $\frac{1}{6}$
- $\frac{2}{3}$
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The Correct Option is
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