Question:medium

If '\(\omega\)' is the angular frequency and '\(k\)' is the wave number representing a photon of energy \(E\) and momentum \(P\) through the wave function \[ \psi(x,t)=A\sin(kx-\omega t) \] Which of the following relation is true

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Photon energy is proportional to angular frequency.
Updated On: Jun 26, 2026
  • \(E=kP\)
  • \(P=\omega E\)
  • \(P=\dfrac{\omega}{k}E\)
  • \(E=\dfrac{\omega}{k}P\)
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The Correct Option is D

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