Question:medium
If $^{n}C_{2017} = {}^{n}C_{2016}$, then $^{n}C_{4033}$ equals
If $^{n}C_{2017} = {}^{n}C_{2016}$, then $^{n}C_{4033}$ equals
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Whenever consecutive combinations are equal, the index lies exactly at the middle of the row in Pascal's Triangle.
Updated On: Apr 30, 2026
- $1$
- $2016$
- $2017$
- $2033$
- $2019$
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The Correct Option is A
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