Question:medium
If light waves of wavelengths \(\lambda\) and \(\lambda/3\) are incident on the surface of a material, photoelectrons are emitted with maximum kinetic energy \(E\) and \(4E\) respectively, then the work function of the material is
If light waves of wavelengths \(\lambda\) and \(\lambda/3\) are incident on the surface of a material, photoelectrons are emitted with maximum kinetic energy \(E\) and \(4E\) respectively, then the work function of the material is
Show Hint
Photoelectric equation: \(K_{\text{max}} = \frac{hc}{\lambda} - \phi\).
Updated On: Apr 24, 2026
- \(\frac{hc}{2\lambda}\)
- \(\frac{hc}{3\lambda}\)
- \(\frac{hc}{\lambda}\)
- \(\frac{2hc}{3\lambda}\)
- \(\frac{3hc}{2\lambda}\)
Show Solution
The Correct Option is A
Solution and Explanation
Was this answer helpful?
0
Top Questions on Photoelectric Effect
- The difference between threshold wavelengths for two metal surfaces \( A \) and \( B \) having work functions \( \phi_A = 9 \, \text{eV} \) and \( \phi_B = 4.5 \, \text{eV} \) is: \[ \text{(Given: } h c = 1242 \, \text{eV nm)} \]
- MHT CET - 2024
- Physics
- Photoelectric Effect
- The maximum kinetic energy of the photoelectrons varies.
- MHT CET - 2024
- Physics
- Photoelectric Effect
- The work function of a metal is 2 eV. What is the threshold frequency for the photoelectric emission? (Take Planck's constant $ h = 6.63 \times 10^{-34} \, \text{Js} $, $ 1 \, \text{eV} = 1.6 \times 10^{-19} \, \text{J} $)
- BITSAT - 2025
- Physics
- Photoelectric Effect
- If \(\phi\) is the work function of photosensitive material in eV and light of wavelength of numerical value \(\lambda = \frac{hc}{e}\) metre, is incident on it with energy above its threshold value at an instant then the maximum kinetic energy of the photo-electron ejected by it at that instant (Take \(h\)-Planck’s constant, \(c\)-velocity of light in free space) is (in SI units):
- NEET (UG) - 2024
- Physics
- Photoelectric Effect
- Want to practice more? Try solving extra ecology questions todayView All Questions
