Question:medium

If \(θ\) is the acute angle between the lines \(2x^2+7xy+3y^2 = 0\), then the value of \(\frac{2cosθ-3sinθ}{4sinθ+5cosθ} = \ldots\)

Show Hint

Factor the pair and find tan theta between the lines.
Updated On: Oct 1, 2026
  • \(1\)
  • \(\frac{5}{9}\)
  • \(-\frac{1}{9}\)
  • \(\frac{1}{9}\)
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Use the formula for pair of lines
For $ax^2+2hxy+by^2=0$, $\tan\theta = \frac{2\sqrt{h^2-ab}}{|a+b|}$. Here $a=2, 2h=7, b=3$.

Step 2: Compute
$h^2-ab = \frac{49}{4}-6 = \frac{25}{4}$, so $2\sqrt{h^2-ab} = 5$ and $a+b = 5$. Hence $\tan\theta = 1$.

Step 3: Evaluate
Divide numerator and denominator by $\cos\theta$: $\frac{2-3\tan\theta}{4\tan\theta+5} = \frac{2-3}{4+5} = -\frac19$. Option (C).

Final Answer:
-1/9. \[ \boxed{\text{(C)}\ -\frac19} \]
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