Question:medium
If \( \int_{-\sqrt{3}}^{1} (-6x^2 + 18)\,dx = \alpha + \beta\sqrt{3} \), then the value of \( \alpha + \beta \) is equal to
If \( \int_{-\sqrt{3}}^{1} (-6x^2 + 18)\,dx = \alpha + \beta\sqrt{3} \), then the value of \( \alpha + \beta \) is equal to
Show Hint
Always compute upper limit minus lower limit carefully with signs.
Updated On: Apr 21, 2026
- \(12 \)
- \(18 \)
- \(24 \)
- \(28 \)
- \(32 \)
Show Solution
The Correct Option is D
Solution and Explanation
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