If in a nuclear fusion process, the masses of the fusing nuclei are m1 and m2 and the mass of the resultant nucleus is m3, then
m3=|m1–m2|
m3 < (m1+m2)
m3>(m1+m2)
m3=m1+m2
In a nuclear fusion process, two lighter nuclei combine to form a heavier nucleus. One of the key aspects of nuclear fusion is the mass-energy relationship governed by Einstein's mass-energy equivalence principle. According to this principle, the mass lost during the fusion process is converted into energy:
The equation for the mass-energy equivalence is given by:
E = \Delta m \cdot c^2
Where:
In this process, the mass of the resultant nucleus m_3 is less than the sum of the initial masses m_1 and m_2. Therefore, the correct relationship is:
m_3 < (m_1 + m_2)
This is because the mass difference (m_1 + m_2 - m_3) is converted into energy according to the mass-energy equivalence principle, explaining the immense energy release during nuclear fusion.
Thus, the correct answer is:
m_3 < (m_1 + m_2)
The electric potential at the surface of an atomic nucleus \( (z = 50) \) of radius \( 9 \times 10^{-13} \) cm is \(\_\_\_\_\_\_\_ \)\(\times 10^{6} V\).
In a nuclear fission reaction of an isotope of mass \( M \), three similar daughter nuclei of the same mass are formed. The speed of a daughter nuclei in terms of mass defect \( \Delta M \) will be: