Question

If in a certain language 'BLANCH' is coded as '36' and 'ARAB' is coded as '24'. What is the code for 'CORRECT'?

• A. 42
• B. 41
• C. 39
• D. 40

Hint:

Always sum the positional values of letters (A=1, B=2...) first in such coding problems.

Answer 1

The Correct Option is A

Step 1: Read the clues.
BLANCH is coded as 36 and ARAB is coded as 24. We must find the code for CORRECT.

Step 2: Count the letters.
BLANCH has 6 letters. ARAB has 4 letters. Let us see if the length matters.

Step 3: Find the rule.
For BLANCH, $6 \times 6 = 36$, which matches. For ARAB, $4 \times 6 = 24$, which also matches. So the rule is number of letters times 6.

Step 4: Count letters of CORRECT.
CORRECT has 7 letters.

Step 5: Apply the rule.
So the code is $7 \times 6 = 42$.

Step 6: Conclusion.
The code for CORRECT is \[ \boxed{42} \]