Question:easy

If \(g(x)\) is the inverse function of \(f(x)\), where \(f(x) = \frac{5x+3}{4x-1}\), then \(g(1) =\)

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\(g(1)\) is the number \(x\) for which \(f(x) = 1\).
Updated On: Oct 1, 2026
  • \(-4\)
  • \(\frac{-1}{4}\)
  • \(\frac{8}{3}\)
  • \(\frac{3}{8}\)
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The Correct Option is A

Solution and Explanation

Step 1: Plan:
Find the full inverse and then put $x = 1$.

Step 2: Inverse:
Let $y = \frac{5x+3}{4x-1}$. Then $4xy - y = 5x + 3$, so $x(4y-5) = y + 3$ and $x = \frac{y+3}{4y-5}$. So $g(y) = \frac{y+3}{4y-5}$.
$g(1) = \frac{4}{-1} = -4$.

Final Answer:
$g(1) = -4$, option (A). \[ \boxed{-4} \]
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