Question:medium

If \(\frac{x^3}{z^2}<\frac{x^3+y^3+z^3}{x^2+y^2+z^2}<\frac{z^3}{x^2}\); \(x, y, z\) are positive real numbers, then which of the following options always ensure the given inequality to be true?

Show Hint

Substitute simple values like \(x=1, y=2, z=3\) to verify the inequality holds.
Updated On: Feb 17, 2026
  • \(y>z>x\)
  • \(z>x>y\)
  • \(x<z>y\)
  • \(x<y<z\)
Show Solution

The Correct Option is D

Solution and Explanation

Strategy:

The middle term is an average-like quantity.
The lower bound is \(\frac{x^3}{z^2}\). For this to be the smallest value, \(x\) should be small and \(z\) should be large.
The upper bound is \(\frac{z^3}{x^2}\). For this to be the largest value, \(z\) should be large and \(x\) should be small.
This suggests \(x\) is the smallest variable and \(z\) is the largest.
\(y\) lies in between.
Order: \(x<y<z\).
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