Step 1: Take logarithmic derivative of \(F(x) = \frac{x^2+1}{(x^2+5)(x^2+9)}\).
\(\ln F = \ln(x^2+1)-\ln(x^2+5)-\ln(x^2+9)\).
\[\frac{F'}{F} = \frac{2x}{x^2+1}-\frac{2x}{x^2+5}-\frac{2x}{x^2+9}\]
Step 2: Read off \(f, g, h\).
Comparing with \(2x F(x)\left[\frac{1}{f(x)}-\frac{1}{g(x)}-\frac{1}{h(x)}\right]\): \(f(x)=x^2+1,\; g(x)=x^2+5,\; h(x)=x^2+9\).
Step 3: Compute the required expression.
\[2h(x)-f(x)-g(x) = 2(x^2+9)-(x^2+1)-(x^2+5) = 2x^2+18-x^2-1-x^2-5 = 12\]
\[ \boxed{12} \]