Question:medium
If $\frac{(1+i)(2+3i)(3-4i)}{(2-3i)(1-i)(3+4i)} = a + ib$, then $a^2 + b^2 =$
If $\frac{(1+i)(2+3i)(3-4i)}{(2-3i)(1-i)(3+4i)} = a + ib$, then $a^2 + b^2 =$
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Don't waste time multiplying out complex fractions if you only need the modulus ($a^2 + b^2$). If every term on top has a corresponding conjugate on the bottom, the modulus is guaranteed to be 1.
Updated On: May 2, 2026
- $132$
- $25$
- $144$
- $128$
- $1$
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The Correct Option is
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