Step 1: Conceptual Understanding:
Continuity of a composed function does not necessarily imply continuity of the inner function. Step 2: Explanation in Detail:
Counter-example: $f(x) = 1$ for $x \ge 0$ and $f(x) = -1$ for $x<0$.
Then $|f(x)| = 1$ is continuous everywhere, but $f(x)$ is discontinuous at $x = 0$. Step 3: Therefore, Stating the Final Answer
Continuity of $|f(x)|$ does not guarantee continuity of $f(x)$.